In Galilean relativity, only the component of velocity that is in the direction of the relative motion of reference frames transforms between the two frames. For example, if the relative motion between frames is \(x\)-direction, the \(x\)-component of the velocity transforms but not the \(y\)-component:
If \(\vec{V} = V\hat{x}\)
Then Galilean boost: \begin{align*} v_x' &= v_x - V\\ v_y' &= v_y \end{align*}
I have shown that for a similar situation in special relativity (where the relative velocity is in the \(x\)-direction), the \(x\)-component of velocity transforms:
\[ v'_x = \frac{v_x-V}{1-\frac{v_x V}{c^2}}\]
Show that, in special relativity, the vertical component also transforms (i.e., find the equation of the transformation).
(Taylor 15.22)
A rocket is traveling at speed 0.9c along the x axis of frame \(S\). It shoots a bullet whose velocity \(v'\) (measured in the rocket's rest frame \(S'\)) is 0.9c along the \(y'\) axis. What is the bullet's velocity (magnitude and direction) as measured in \(S\)?